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2x^2-2.666x-802.56=0
a = 2; b = -2.666; c = -802.56;
Δ = b2-4ac
Δ = -2.6662-4·2·(-802.56)
Δ = 6427.587556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.666)-\sqrt{6427.587556}}{2*2}=\frac{2.666-\sqrt{6427.587556}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.666)+\sqrt{6427.587556}}{2*2}=\frac{2.666+\sqrt{6427.587556}}{4} $
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